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4x^2+28x-3x-21=0
We add all the numbers together, and all the variables
4x^2+25x-21=0
a = 4; b = 25; c = -21;
Δ = b2-4ac
Δ = 252-4·4·(-21)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-31}{2*4}=\frac{-56}{8} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+31}{2*4}=\frac{6}{8} =3/4 $
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